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Ekponenjika y = 3ˣ
nyatakan dalam y
b. 3²ˣ ⁺ ¹ - 3ˣ⁻²= (3ˣ)² .(3)¹ - (3)ˣ. (3⁻²)
= y² (3) - y (1/9)
= 3y² - 1/9 y
c. 2 (3¹⁻ˣ) = 2. 3¹. 3⁻ˣ
= 6. (3ˣ)⁻¹
= 6 y⁻¹
= 6/y
d. (3)ˣ + 3ˣ ⁺ ¹ + 3ˣ ⁺ ² =
= (3ˣ) + (3)ˣ . 3¹ + (3ˣ)⁻²
= y + y(3) + y⁻²
= 4y + y⁻²
= 4y + 1/y²
e. 9ˣ - 27^(¹/₃x + ²/₃) =
= (3ˣ)² - (3³)^(1/3x + 2/3)
= (3x)² - (3)ˣ⁺²
= (3ˣ)² - (3ˣ). (3²)
= y² - y(9)
= y² - 9y
f. 3ˣ - 9^(1/2 x +1) + (27)^(1/3(x+2))
= (3ˣ) -(3²)^(1/2x + 1) + (3³)^(1/3 (x+2))
= (3ˣ) - (3)ˣ⁺² + (3)ˣ⁺²
= (3ˣ) - (3ˣ) (3²) + (3ˣ) (3²)
= (y) - (y)(9) + (y)(9)
= y - 9y + 9y
= y