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q₁ = 2μC = 2×10⁻⁶ C
q₂ = 18 mC = 18×10⁻³ C
r = 2 cm = 2×10⁻² m
F, E = __ ?
Gaya interaksi antar kedua muatan
F = k q₁ q₂ / r²
= (9×10⁹ Nm²C⁻²) (2×10⁻⁶ C) (18×10⁻³ C) / (2×10⁻² m)²
= 8,1×10⁵ N ← jwb
Kuat medan listrik di A
Ea = k q₂ / r² = F / q₁
= (8,1×10⁵ N) / ((2×10⁻⁶ C))
= 4,05×10¹¹ N/C ← jwb
Kuat medan listrik di B
Eb = k q₁ / r² = F / q₂
= (8,1×10⁵ N) / ((18×10⁻³ C))
= 4,5×10⁷ N/C ← jwb
Lihat gambar terlampir sebagai penjelas