Respuesta:
D) 1
Explicación paso a paso:
Sustituye x & y
P= (1993^2 - (-1992)^2)^2 + 4 (1993)+(-1992) = 1
Espero ayudarte :-)
1
Sale 1 pues por productos notables:
[tex]({x}^{2} - {y}^{2} ) {}^{2} + 4xy[/tex]
[tex] (x - y) {}^{2} (x + y) {}^{2} + 4xy[/tex]
[tex](x - y) {}^{2} (1993 - 1992) {}^{2} + 4xy[/tex]
[tex](x - y) {}^{2} + 4xy[/tex]
[tex]x {}^{2} - 2xy + y {}^{2} + 4xy[/tex]
[tex]x {}^{2} + 2xy + y {}^{2} [/tex]
[tex](x + y) {}^{2} [/tex]
[tex](1993 - 1992) {}^{2} [/tex]
[tex]1[/tex]
Espero que me hayas entendido
Suerte :)
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Respuesta:
D) 1
Explicación paso a paso:
Sustituye x & y
P= (1993^2 - (-1992)^2)^2 + 4 (1993)+(-1992) = 1
Espero ayudarte :-)
Verified answer
1
Explicación paso a paso:
Sale 1 pues por productos notables:
[tex]({x}^{2} - {y}^{2} ) {}^{2} + 4xy[/tex]
[tex] (x - y) {}^{2} (x + y) {}^{2} + 4xy[/tex]
[tex](x - y) {}^{2} (1993 - 1992) {}^{2} + 4xy[/tex]
[tex](x - y) {}^{2} + 4xy[/tex]
[tex]x {}^{2} - 2xy + y {}^{2} + 4xy[/tex]
[tex]x {}^{2} + 2xy + y {}^{2} [/tex]
[tex](x + y) {}^{2} [/tex]
[tex](1993 - 1992) {}^{2} [/tex]
[tex]1[/tex]
Espero que me hayas entendido
Suerte :)