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x + 3 = x² - 4
x² - 4 - x - 3 = 0
x² - x - 7 = 0
a = 1
b = -1
c = -7
gunakan rumus abc untuk mencari x
sehingga ditemukan 2 nilai x, yaitu :
x1 = (1 + √29)/2
x2 = (1 - √29)/2
y = x + 3
y = (1 + √29)/2 + 3
y = (1 + √29)/2 + 6/2
y = (7 + √29)/2
y = (1 - √29)/2 + 3
y = (1 - √29)/2 + 6/2
y = (7 - √29)/2
jadi nilai yang memenuhi adalah :
x,y = (1 + √29)/2 , (7 + √29)/2
x,y = (1 - √29)/2 , (7 - √29)/2