Question

Xy/z+yz/x+zx/y+ x^{-1}+y^{-1} +z^{-1}
Si x=1 y=-2 z=3

Answer 1

Como: x= 1; y= -2 y z= 3, tenemos:

=Xy/z+yz/x+zx/y+ x^{-1}+y^{-1} +z^{-1}
=(1)(-2)/3 +(-2)(3)/1+(3)(1)/-2 +1^{-1}+(-2)^{-1} +3^{-1}
= - 2/3 - 6 - 3/2 +1 +1/-2 + 1/3...ordenando
= (-2/3 +1/3 -1/2 -3/2) - 6 + 1
=(-1/3 - 4/2) - 5
=(-1/3 -2) -5
= -1/3 -7
= (-1x1-3x7)/3
= (-1-21)/3
= -22/3