Respuesta:
12.- C)
13.- C)
14.- B)
15.- C)
Explicación paso a paso:
[tex]12. \\ {( {w}^{4} {z}^{2} )}^{3} \\ {w}^{4 \times 3} {z}^{2 \times 3} \\ {w}^{12} {z}^{6} [/tex]
[tex]13. \\ \frac{ {b}^{7} }{ {b}^{2} } = {b}^{7 - 2} = {b}^{5} [/tex]
[tex]14. \\ \frac{ {x}^{8} }{ {x}^{8} } = {x}^{8 - 8} = {x}^{0} [/tex]
[tex]15. \\ {y}^{ - 2} = \frac{ {y}^{ - 2} }{1} = \frac{1}{ {y}^{ 2} } [/tex]
w12z6
b5
x0
(w4z2)3 se multiplica w12z6
b7/b2 se resta b5
x8x8 se resta x0
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Verified answer
Respuesta:
12.- C)
13.- C)
14.- B)
15.- C)
Explicación paso a paso:
[tex]12. \\ {( {w}^{4} {z}^{2} )}^{3} \\ {w}^{4 \times 3} {z}^{2 \times 3} \\ {w}^{12} {z}^{6} [/tex]
[tex]13. \\ \frac{ {b}^{7} }{ {b}^{2} } = {b}^{7 - 2} = {b}^{5} [/tex]
[tex]14. \\ \frac{ {x}^{8} }{ {x}^{8} } = {x}^{8 - 8} = {x}^{0} [/tex]
[tex]15. \\ {y}^{ - 2} = \frac{ {y}^{ - 2} }{1} = \frac{1}{ {y}^{ 2} } [/tex]
Respuesta:
w12z6
b5
x0
(w4z2)3 se multiplica w12z6
b7/b2 se resta b5
x8x8 se resta x0