Question

(x+y)^5 = x^5 + ax^4y + bx^3y^2 + cx^2y^3 + dxy^4 + y^5. Hasil 3a+2b =..... please kalau bisa dengan caranya ya... Tks

Answer 1

Pakai pitagoras

1
1 1
2 =1 2 1
3 = 1 3 3 1
4 = 1 4 6 4 1
5 = 1 5 10 10 5 1

jadi 5 + 10 + 10 + 5 = 30