xy(x + y) = 308
xy = 308/(x + y)
substitusi ke persamaan:
xy + x + y = 39
[308/(x + y)] + (x + y) = 39
kedua ruas kalikan dengan (x + y) :
308 + (x + y)² = 39(x + y)
(x + y)² - 39(x + y) + 308 = 0
(x + y - 11)(x + y - 28) = 0
x + y = 11 atau x + y = 28
ig : @insanbm
Telegram : @math_solve
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Verified answer
xy(x + y) = 308
xy = 308/(x + y)
substitusi ke persamaan:
xy + x + y = 39
[308/(x + y)] + (x + y) = 39
kedua ruas kalikan dengan (x + y) :
308 + (x + y)² = 39(x + y)
(x + y)² - 39(x + y) + 308 = 0
(x + y - 11)(x + y - 28) = 0
x + y = 11 atau x + y = 28
ig : @insanbm
Telegram : @math_solve