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-2x + 6y = 10 |x1| -2x + 6y = 10
trus di eliminasi =
-4y = -12
y= 3
trus subtitusikan =
-2x + 2y = -2
-2x = -2 - 6
x = -8 / -2
x = 4
jd x,y = 4,3
-x + y = -1 x2 -2x + 2y = -2 -4y = 12, nilai y = 3
-2x + 6y = 10 x1 -2x + 6y = 10 -x + 3 = -1, -x = -4, x = 4
nilai x = 4, nilai y = 3...