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f(12/x) = (12'log 12 - 12'log x) / (1 - 2. {12'log 12 - 12'log x})
f( 12/x ) = ( 1- 12'log x ) / [ 1- 2 (1 - 12'log x)]
f( 12/x ) = ( 1 - 12'log x) / - (1 - 2.12'log x)
..
f(x) + f( 12/x ) = 12'log x / (1 - 2. 12'log x) + (1- 12'log x)/ - (1 - 2.12'log x)
= (12''log x- 1 + 12'log x) / (1 - 2. 12'log x)
= ( 2. 12'log x - 1) / - ( 2. 12'log x - 1)
= -1