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y =x-3/2x+1
2xy +y =x-3
2xy - x = -y -3
x(2y -1) =-y -3
f(x)' = (-y-3)/ (2y-1)
b.f(x)=x-2/x-3
y =x-2/x-3
xy -3y =x-2
xy - x = 3y-2
x(y -1) =3y -2
f(x)' = (3y-2)/ (y-1)
c.f(x)=2-3x/3x
y=2-3x/3x
3xy=2-3x
3xy + 3x =2
x(3y + 3) = 2
f(x)' = 2/(3y+3)