Question

(x+3)kuadrat
(x-2)pangkat tiga

Answer 1

1. (x + 3)² = (x + 3)(x + 3) =(x)(x) + (x)(3) + (3)(x) + (3)(3) = x² + 3x + 3x + 9 = x² + 6x + 9

2. (x - 2)³ = (x-2)(x-2)(x-2)
  =( (x)(x) + (x)(-2) + (-2)(x) + (-2)(-2) )(x-2) 
  =( x² - 2x - 2x + 4)(x-2)
  =(x² - 4x + 4)(x-2)
  =(x²)(x) + (x²)(-2) + (-4x)(x) + (-4x)(-2) + (4)(x) + (4)(-2)
  = x³ - 2x² - 4x² + 8x + 4x - 8
  = x³ - 6x² + 12x - 8