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g(x)+1 = 2x/(x+3)
diselesaikan dengan menggunakan aljabar biasa, maka didapatkan:
g(x) = (x-3)/(x+3)
⇔f(g(x)) = 2x/x+3
⇔g(x) + 1 = 2x/x+3
⇔g(x) = (2x/x+3) - 1
⇔g(x) = (2x/x+3) - (x+3/x+3)
⇔g(x) = [2x-(x+3)]/(x+3)
⇔g(x) = (x-3)/(x+3)