Question

Nilai dari lim x~2 (x^2+x-6)/ (x^3-8)

Answer 1

Lim(x->2) (x+3)(x-2) / (x -2)(x² + 2x + 4)
coret (x-2) 
= (x+3) / (x² + 2x + 4)
sub x = 2
= (2+3)/ (4+4+ 4)
= 5/12

atau pake dhospital
= (2x + 1)/(3x²) 
x= 2 --> (5)/(12)