Respuesta:
[tex](2a+b+c)(x-1)[/tex]
Explicación paso a paso:
[tex]Factorizar:[/tex]
[tex]x(2a+b+c)-2a-b-c[/tex]
[tex]Buscamos -factor-comun-monomio-de: -2a-b-c[/tex]
[tex]-1(2a+b+c)[/tex]
[tex]Entonces: x(2a+b+c) -2a-b-c = x (2a+b+c) -1(2a+b+c)[/tex]
[tex]Buscando -factor-comun-polinpmio:[/tex]
[tex]Luego: x(2a+b+c)-2a-b-c = (2a+b+c)(x-1)[/tex]
[tex]= (2a+b+c)(x-1)[/tex]
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.
Verified answer
Respuesta:
[tex](2a+b+c)(x-1)[/tex]
Explicación paso a paso:
[tex]Factorizar:[/tex]
[tex]x(2a+b+c)-2a-b-c[/tex]
[tex]Buscamos -factor-comun-monomio-de: -2a-b-c[/tex]
[tex]-1(2a+b+c)[/tex]
[tex]Entonces: x(2a+b+c) -2a-b-c = x (2a+b+c) -1(2a+b+c)[/tex]
[tex]Buscando -factor-comun-polinpmio:[/tex]
[tex]Luego: x(2a+b+c)-2a-b-c = (2a+b+c)(x-1)[/tex]
[tex]= (2a+b+c)(x-1)[/tex]