Explicación paso a paso:
[tex] {x}^{2} + 6x + 9 = 0 \\ x = \frac{ - b + - \sqrt{ {b - }^{2} 4ac} }{2a} = \\ \frac{ - 6 + - \sqrt{ {6 }^{2} - 4 \times 1 \times 9} }{2 \times 1} \\ \frac{ - 6 + - \sqrt{36 - 36} }{2} = \frac{ - 6 + - 0}{2} = - 3[/tex]
[tex] ({ - 3}^{} ) {}^{2} + 6( - 3) + 9 = 9 + ( - 18) + 9 = 0[/tex]
espero te sirva
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Explicación paso a paso:
[tex] {x}^{2} + 6x + 9 = 0 \\ x = \frac{ - b + - \sqrt{ {b - }^{2} 4ac} }{2a} = \\ \frac{ - 6 + - \sqrt{ {6 }^{2} - 4 \times 1 \times 9} }{2 \times 1} \\ \frac{ - 6 + - \sqrt{36 - 36} }{2} = \frac{ - 6 + - 0}{2} = - 3[/tex]
[tex] ({ - 3}^{} ) {}^{2} + 6( - 3) + 9 = 9 + ( - 18) + 9 = 0[/tex]
espero te sirva