Tolong dijawab ya...sederhanakanlah bentuk pecahan aljabar berikut dan tulislah langkah-langkahnya :.... Question from @khanzhenda

August 2018 2 15 Report

Tolong dijawab ya...
sederhanakanlah bentuk pecahan aljabar berikut dan tulislah langkah-langkahnya :
1. 3/x+1 + 3/x-1 = ?
2. 3x^2-27/x^2+2x-3 = ?

hilmianggraeni 1. $\frac{6}{2x}$

0 votes Thanks 2

otek 1. menyamakan penyebutnya.
$\frac{3}{x+1} + \frac{3}{x-1}$ = $\frac{3(x-1)}{(x+1)(x-1)} + \frac{3(x+1)}{(x+1)(x-1)}$
$= \frac{3x-3+3x+3}{(x+1)(x-1)}$
$= \frac{6x}{ x^{2} +1}$

2. memfaktorkan
$\frac{ 3x^{2}-27 }{ x^{2} +2x-3} = \frac{3( x^{2}-9)}{(x+3)(x-1)} = \frac{ 3(x^{2} - 3^{2}) }{(x+3)(x-1)}$

= $\frac{3(x+3)(x-3)}{(x+3)(x-1)} = \frac{3(x-3)}{x-1}= \frac{3x-9}{x-1}$

2 votes Thanks 3

otek ngerti gak

otek kamu udah belajar pemfaktoran belum

khanzhenda oke ngerti makasih

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