Question

x^{2} (x+4) =

(3x-4)(2x+7) =

(2x^{2}-4x+5)(3x+1) =

(p2-1)(p2+p-1)=

(x-y)(2x+y)(x+2y)=
.
Aljabar MTK Fast PR Gan kASIH 20 Point dah[tex] x^{2} = xPangkat 2

Answer 1

X^2 (x+4)
= x^3 + 4 x^2

(3x-4) (2x+7)
= 6x^2 + 21x - 8x - 28
= 6x^2 + 13x - 28

(2x^2 - 4x + 5) ( 3x + 1)
= 6x^3 + 2x^2 - 12x^2 - 4x + 15x + 5
= 6x^3 - 10x^2 + 11x +5

(p2-1) (p2+p-1)
= 2p4 + 2p2 - p2 - p2 - p + 1
= 2p4 + 2p2 - 2p4 - p + 1
=2p2 - p + 1

(x-y) (2x+y) (x+2y)
= (2x^2 + xy - 2xy - y) ( x + 2y)
= (2x^2 -xy -y) ( x + 2y)
= 2x^3 + 2x^2y - x^2y - 2xy^2 - xy - 2y^2
= 2x^3 + x^2y - 2xy^2 - xy - 2y^2