Question

Jika f(x)=1/√(x^2-2) dan (fog)(x)= 1/√(x^2-6x+7) tentukan nilai g(x+2)
tolong bantu ya

Answer 1

(f o g)(x) = f(g(x))
1/akar(x^2-6x+7) = 1/akar( (g(x))^2 -2 )
hilangin 1/akar nya
x^2-6x+7 = g(x)^2 - 2
x^2-6x+9 = g(x)^2
(x-3)^2 = g(x)^2
g(x) = x-3

g(x+2) = (x+2)-3 = x-1