Respuesta:
(x+1) (x+2)
Explicación:
[tex]x^{2}[/tex] + 3x + 2= 0
a=1 ; b=3 ; c=2
x=[tex]\frac{-b\pm \sqrt{b^{2}-4ac } }{2a}[/tex]
x= [tex]\frac{-3\pm \sqrt{3^2-4\cdot \:1\cdot \:2}}{2\cdot \:1}[/tex]
x= [tex]\frac{-3\pm \:1}{2\cdot \:1}[/tex]
x1= [tex]\frac{-3+1}{2\cdot \:1}[/tex] = -1
x2= [tex]\frac{-3-1}{2\cdot \:1}[/tex]= -2
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Respuesta:
(x+1) (x+2)
Explicación:
[tex]x^{2}[/tex] + 3x + 2= 0
a=1 ; b=3 ; c=2
x=[tex]\frac{-b\pm \sqrt{b^{2}-4ac } }{2a}[/tex]
x= [tex]\frac{-3\pm \sqrt{3^2-4\cdot \:1\cdot \:2}}{2\cdot \:1}[/tex]
x= [tex]\frac{-3\pm \:1}{2\cdot \:1}[/tex]
x1= [tex]\frac{-3+1}{2\cdot \:1}[/tex] = -1
x2= [tex]\frac{-3-1}{2\cdot \:1}[/tex]= -2
(x+1) (x+2)