Odpowiedź:
[tex]\displaystyle \frac{3}{x+5} -\frac{1}{x-5} +\frac{30}{x^{2} -25} \quad x\ne5\quad x\ne-5\\\frac{3}{x+5} -\frac{1}{x-5} +\frac{30}{(x-5)(x+5)} =\frac{3(x-5)-(x+5)+30}{(x-5)(x+5)} =\\\frac{3x-15-x-5+30}{(x-5)(x+5)} =\frac{2x+10}{(x-5)(x+5)} =\frac{2(x+5)}{(x-5)(x+5)} =\\=\frac{2}{x-5}[/tex]
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Odpowiedź:
[tex]\displaystyle \frac{3}{x+5} -\frac{1}{x-5} +\frac{30}{x^{2} -25} \quad x\ne5\quad x\ne-5\\\frac{3}{x+5} -\frac{1}{x-5} +\frac{30}{(x-5)(x+5)} =\frac{3(x-5)-(x+5)+30}{(x-5)(x+5)} =\\\frac{3x-15-x-5+30}{(x-5)(x+5)} =\frac{2x+10}{(x-5)(x+5)} =\frac{2(x+5)}{(x-5)(x+5)} =\\=\frac{2}{x-5}[/tex]