Question

Akar-akar persamaan kuadrat 3x-x+9=0 adalah X1 dan X2 nilai dari X1/X2 + X2/X1=

Answer 1

A=3, b= -1, c= 9
x1+x2= -b/a = -1/3
x1 . x2 = c/a = 9/3 = 3
maka, x1/x2 + x2/x1 = x1²+x2²/x1.x2
=(x1+x2)² - 2.x1.x2/x1.x2
=(-1/3)² - 2.3 / 3
=1/9 - 6 / 3
= -53/9 / 3
= -53/27

Answer 2

X1 + x2 = -b/a = 1/3
x1x2 = c/a = 3
x1/x2 + x2/x1 = (x1² + x2²)/x1x2
= (1/3)² - 2x1x2 / x1x2
= 1/9 - 2(3) / 3
= 1/9 - 6 / 3
= -53/9 / 3
= -53/27