|x+1|=|2x-3| Tentukan hp persamaan nya.... Question from @Vlarra

April 2019 2 8 Report

|x+1|=|2x-3|
Tentukan hp persamaan nya

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Kuadratkan kedua ruas
$(x+1)^2=(2x-3)^2$
$(x+1)^2-(2x-3)^2=0$
$[(x+1)+(2x-3)][(x+1)-(2x-3)]=0$
$(3x-2)(4-x)=0$
$x=\frac{2}{3} \vee x=4$

0 votes Thanks 2

BeetSha

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|x + 1| = |2x - 3|
(x + 1)² = (2x - 3)²
x² + 2x + 1 = 4x² - 12x + 9
x² - 4x² + 2x + 12 x + 1 - 9 = 0
-3x² + 14x - 8 = 0
3x² - 14x + 8 = 0
3x² - 12x - 2x + 8 = 0
3x(x - 4) - 2(x - 4) = 0
(x - 4)(3x - 2) = 0
x - 4 = 0 atau 3x - 2 = 0
x = 4 atau 3x = 2
x = 4 atau x = $\bold{ \frac{2}{3}}$

HP = { $\bold{ \frac{2}{3}}$ , 4}

1 votes Thanks 3

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