Explicación paso a paso:
[tex]2x + y = 5 \\ 2x = 5 - y \\ x = \frac{5 - y}{2} \\ x - y = 2 \\ x = 2 + y \\ 2 + y = \frac{5 - y}{2} \\ 4 + 2y = 5 - y \\ y + 2y = 5 - 4 \\ 3y = 1 \\ y = \frac{1}{3} [/tex]
[tex]x = 2 + y = 2 + \frac{1}{3} = \frac{6}{3} + \frac{1}{3} = \frac{7}{3} \\ x = \frac{7}{3} [/tex]
[tex]2 \times \frac{7}{3} + \frac{1}{3} = \frac{14}{3} + \frac{1}{3} = \frac{15}{3} = 5[/tex]
[tex] \frac{7}{3} - \frac{1}{3} = \frac{6}{3} = 2[/tex]
espero te sirva
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Verified answer
Explicación paso a paso:
[tex]2x + y = 5 \\ 2x = 5 - y \\ x = \frac{5 - y}{2} \\ x - y = 2 \\ x = 2 + y \\ 2 + y = \frac{5 - y}{2} \\ 4 + 2y = 5 - y \\ y + 2y = 5 - 4 \\ 3y = 1 \\ y = \frac{1}{3} [/tex]
[tex]x = 2 + y = 2 + \frac{1}{3} = \frac{6}{3} + \frac{1}{3} = \frac{7}{3} \\ x = \frac{7}{3} [/tex]
[tex]2 \times \frac{7}{3} + \frac{1}{3} = \frac{14}{3} + \frac{1}{3} = \frac{15}{3} = 5[/tex]
[tex] \frac{7}{3} - \frac{1}{3} = \frac{6}{3} = 2[/tex]
espero te sirva