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x + 2x/3 + x/2 = 13
(6x + 4x + 3x) per 6 = 13
13 x = 13 (6)
x = 6
diubah ke z semua :
2z + 4/3z + z = 13
(6z + 4z + 3z) per 3 = 13
13 z = 13 (3)
z = 3
substitusi :
x + y + z = 13
6 + y + 3 = 13
y = 13 - 9
y = 4
hitung deh :
x + y - z = 6 + 4 - 3 = 7
Maaf kalau salah,, itu yang saya tau ^_^*