Sean A = {1, 3, 5, 7, 9}
B = {2, 4, 6, 8, 10}
C = {1, 2, 3, 4, 5, 6, 7, 8}
Hallar:
E = [A (B C)’] (A’ – B’)
Siendo:
U = {x/x N x < 12}
a) {9, 11} b) {9, 10, 11} c) {8, 9, 10}
d) {8, 10, 11} e) N.A.
B = {2, 4, 6, 8, 10}
C = {1, 2, 3, 4, 5, 6, 7, 8}
Hallar:
E = [A (B C)’] (A’ – B’)
Siendo:
U = {x/x N x < 12}
a) {9, 11} b) {9, 10, 11} c) {8, 9, 10}
d) {8, 10, 11} e) N.A.
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Respuesta:
A ⊆ B y A ⊆ C =⇒ A ⊆ B ∩ C
Explicación paso a paso: