Question

1) Dada f (t) = 5t + 7, calcule f (1); f (-3); f(c); f (1 + c) y f (1) + f (c).

2) Dada f(t) = 3t^2 - 5t + 7, calcule f (0); f (1/t); f (c) + f (h) y f(c + h).

3)Dada f (x) = 3, calcule f (1/x); f (x^2); f (x + 2) y f (x + h).

Answer 1

1)

f(1) = 5(1) + 7 = 12
f(-3) = 5(-3)+7 = -8
f(c) = 5(c) + 7 = 5c+7
f(1+c) = 5(1+c) + 7 = 5x + 12
f(1) + f(c) = (12) + (5c + 7) = 5c + 19

2)

f(0) = 3(0)²  - 5(0) + 7 = 7
f(1/t) = 3(1/t)² -5(1/t) + 7 = 3/t² - 5/t +7
* f(c) =  3c² - 5c + 7
* f(h) = 3h² - 5h + 7
⇒ f(c) + f(h) = 3(c² + h²) - 5(c + h) + 14
f(c+h) = 3(c+h)² - 5(c+h) + 7

3)  f(x) =3 ........ Funcion constante

f(1/x) =3
f(x^2) = 3
f(x+2)=3
f(x+h) =3