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entonces: 56 < 4n < 82 ⇒ 28 < 2n < 41
donde n = 15, 16, 17, 18, 19, 20
X = 15(4) = 60
X = 16(4) = 64 .......
X = 60, 64, 68, 72, 76, 80
ENTONCES n(A) = 6
suerte XD