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se buscan dos números que multiplicados sean 9 y sumados sean 6, así:
(X-3)(X-3)=0
ya que al multiplicarlos x^2-3x -3x+9 = x^2-6x +9
(X-3)=0
X=3
saludos :)
(x -3) (x -3) = 0
x -3 = 0 x -3 = 0
x₁ = 3 x₂ = 3