Question

Lim 1-cos(3x-1)/x²-6x+9=...
x⇒0

Answer 1

Lim (1 - (1 - 2 sin²(3/2 x - 1/2)) / (x - 3)²
x->0
= lim 2sin²(3/2 x - 1/2)/(x - 3)²
x->0
masukan x = 0
2(-1/2)² / 9
= 2(1/4) / 9
= 1/18