Question

mohon bantuannya suhu _/\_
x² + 4x - 5 = 0
carilah akar-akarnya​

Answer 1

Verified answer

x² + 4x - 5 = 0

a = 1

b = 4

c = -5

ABC :

= -4 ± √(4)² - 4(1(-5)/2(1)

= (-4 ± √16 + 20)/2

= (-4 ± √36)/2

= (-4 ± 6)/2

x1 = (-4 - 6)/2 = -10/2 = -5

x2 = (-4 + 6)/2 = (6 - 4)/2 = 2/2 = 1

Hp = {-5 , 1}

Answer 2

Jawaban:

Penyelesaian :

x² + 4x - 5 = 0

• Kuadrat sempurna

[tex]\begin{aligned}\sf {x}^{2} +4x -5 &= \sf 0 \\ \sf {x}^{2} +4x&= \sf 5\\ \sf {x}^{2} +5x + ( \frac{4}{2}) {}^{2} &= \sf 5 + ( \frac{4}{2} ) {}^{2} \\ \sf (x +2) {}^{2} &= \sf 5 + (2)² \\ \sf (x +2) {}^{2}&= \sf 5 +4 \\ \sf ( x +2) {}^{2} &= \sf 9 \\ \sf x +2&= \sf \sqrt{ 9 } \\ \sf x +2 &= \sf ± 3 \\ \\ \sf \to (x+2) &= \sf 3 \\ \sf x&= \sf 3 -2 \\ \sf x&= \sf \red{ 1 } \\ \\ \sf \to (x +2 ) &= \sf - 3 \\ \sf x&= \sf - 3 -2 \\ \sf x&= \sf \red{-5}\end{aligned}[/tex]

[tex] \sf HP = \{ \red{-5 ,1} \}[/tex]

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