Turunan pertama dari fungsi (3x^2 + 6x + 1) (1/x + 3x).... Question from @feliarahmawati

October 2018 2 13 Report

Turunan pertama dari fungsi
(3x^2 + 6x + 1) (1/x + 3x)

nikeey Ini gampang cuma tinggal dikalikan aja kedua persamaannya jadi $3x^{} + 9 x^{3} + 6 + 18 x^{2} + 3 x^{} = 27 x^{2} + 36 x^{} + 9$ :-)

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desi31 = 3x + 9x^3 + 6 + 18x^2 + 1/x + 3x
= 9x^3 + 18x^2 + 6x + x^-1 + 6
= 27x^2 + 36x + 6 + (-1 x^-2)
= 27x^2 + 36x t+ 6 - 1/x^2

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