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f⁻¹ { (2x+1)/(x-3)} = x
misal
y = (2x+1) / (x-3)
2x +1 = y (x-3)
2x + 1 = xy - 3y
2x - xy = -3y -1
x(2-y) = -3y -1
x = (-3y -1)/(-y+2)
atau
x = (3y +1)/(y-2)
f⁻¹(x)= (3x +1)/(x-2)|....