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12 < (x-3)(x+1)
12 < x² -2x -3
0 < x² -2x -15
x² -2x -15 > 0
x² -2x - 15=0
(x-5)(x+3) = 0
x-5 = 0 atau x+3=0
x = 5 x= -3
masukkan ke garis bilangan
+ -3 - 5 +
karena yang dicari >0 bearti positif.
maka HP={ x< -3 atau x> 5}