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Verified answer
| x + 3 | < | x - 1 |(x + 3)² < (x - 1)²
x² + 6x + 9 < x² - 2x + 1
6x + 9 < -2x + 1
6x + 2x < 1 - 9
8x < -8
x < -1
HP : {x| x< -1 , x ∈ R}