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f ' (x) = - 4x⁻² = - 4/x²
2) f(x) = - 2x⁻²
f ' (x) = 4x⁻³ = 4/x³
3) f(x) = 6x^(3/2)
f ' (x) = 6(3/2)x^(1/2)
= 9√x
f(x) = 4.x⁻¹
f'(x) = -4x⁻² =
nomor 2.
f(x) = -2/x²
f(x) = -2.x⁻²
f'(x) = 4.x⁻³ =
nomor 3.
f(x) = 6x √x
= 6.x.
= 6.
f'(x) = 9. = 9√x