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2x + y - 3z = 3 (2)
3x + 3y - 2z = 10 (3)
eliminasi persamaan (1) dan (2)
x - 2y + z = -1 |x2| 2x - 4y + 2z = -2
2x + y - 3z = 3 |x1 | 2x + y - 3z = 3
---------------------------------------------------- –
-5y + 5z = -5 (4)
eliminasi persamaan (1) dan (3)
x - 2y + z = -1 |x3| 3x - 6y + 3z = -3
3x + 3y - 2z = 10 |x1 | 3x + 3y - 2z = 10
---------------------------------------------------- –
-9y + 5z = -13 (5)
eliminasi persamaan (4) dan (5)
-5y + 5z = -5
-9y + 5z = -13
---------------------- –
4y = 8
y = 2
substitusi ke persamaan (4)
-5y + 5z = -5
-5(2) + 5z = -5
-10 + 5z = -5
5z = -5 + 10
5z = 5
z = 1
substitusi ke persamaan (1)
x - 2y + z = -1
x -2(2) + 1 = -1
x - 4 + 1 = -1
x - 3 = -1
x = -1 + 3
x = 2
jadi HP = {(2,2,1)}
semoga membantu :)