Question

|x-2|<|x+1| = tolong bantu soal mutlak

Answer 1

|x-2| < |x+1|
√(x-2)^2 < √(x+1)^2
(x-2)^2 < (x+1)^2
x^2 - 4x + 4 < x^2 + 2x + 1
x^2 - x^2 - 4x - 2x + 4 -1 < 0
-6x + 3 < 0
pembuat nol
-6x + 3 = 0
-6x = -3
x = -3/-6
x = 1/2
Jadi Hp = { x | x > 1/2 }