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=10x/x^2 - 4
=1/(x+2)+4/2(x+3)
=1/(x+2)+1/(x+3)
=[(x+3)+(x+2)]/x²+5x+6
=2x+5/x²+5x+6
B. 5/(x+3) + 5/(x pangkat 2 - 9)
=5/x+3+5/(x+3)(x-3)
=[5(x-3)+5]/(x+3)(x-3)
=5x-15+5/(x+3)(x-3)
=5x-10/x²-9
C. 5/(x+2) + 5/(x-2)
=[5(x-2)+5(x+2)]/(x+2)(x-2)
=5x-10+5x+10/x²-4
=10x/x²-4