Question

Q (1/3) (25+) ;_;

f(x)= 6x + 4/x² × 2(5) + 8x
f(2) + f(3) = ?


nt : cih​

Answer 1

f(x) = 6x + 4 / x² × 2(5) + 8x

f(2) = 6(2) + 4 / 2² × 10 + 8(2)

f(2) = 12 + 4 / 4 × 10 + 16

f(2) = 12 + 10 + 16

f(2) = 12 + 26

f(2) = 38

f(x) = 6x + 4 / x² × 2(5) + 8x

f(3) = 6(3) + 4 / 3² × 10 + 8(3)

f(3) = 18 + 4 / 9 × 10 + 24

f(3) = 22 / 90 + 24

f(3) = 22/114

MAKA :

F(2) + F(3)

= 38 + 22/114

= 38/1 + 11/57

= 2.166/57 + 11/57

= 2.177/57

= 38,19

Answer 2

f(x) = 6x + 4/x² × 2(5) + 8x

f(2) = 6(2) + 4/2² × 10 + 8(2)

f(2) = 12 + 4/4 × 10 + 16

f(2) = 12 + 1 × 10 + 16

f(2) = 12 + 10 + 16

f(2) = 22 + 16

f(2) = 38

f(x) = 6x + 4/x² × 2(5) + 8x

f(3) = 6(3) + 4/3² × 10 + 8(3)

f(3) = 18 + 4/9 × 10 + 24

f(3) = 18 + 40/9 + 24

f(3) = 418/9

f(3) = 46 4/9

Ditanya

f(2) + f(3)

= 38 + 46 4/9

= 38 + 418/9

= 342/9 + 418/9

= 760/9

= 84 4/9

⃢~ Opung~⃠⃫⃟⃤᳗᳐