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(x^2 - 7x + 6)/(x - 1) = (x - 1)(x - 6)/(x - 1) = x - 6
integralkan :
int (x - 6) dx [0,1]
= [1/2 x^2 - 6x] [0,1]
= (1/2 1^2 - 6(1)) - (0 - 0)
= 1/2 - 6
= -11/2