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x² + 11x + 24 = 0 Factorizas trinomio de la forma x² + bx + c
(x + 8)(x + 3) = 0 Tiene como solución dos raices reales distintas
x + 8 = 0
x = - 8
o
x + 3 =
x = - 3
Solución.
(- 8 , - 3)
x +8
x +3
8x+3x = 11x
(x+8)(x+3) = 0
x+8 = 0 x+3 = 0
x= -8 x = -3
CS = (-8; -3)