Question

Wyznaczanie ciepła właściwego

Answer 1

Z1)

m1=1 kg

T1=90°C

T=50°C

T2= 30°C

cw=4200 J/(kgK)

m2=?

m1*cw*(T1-T)=m2*cw*(T-T2)

m2= (m1*(T1-T)) / (T-T2)

m2= (1*40)/20

m2= 2 kg

Z2)

T1=70°C

m1=0,5 kg

T2=28°C

m2=0,3 kg

T=?

m1*cw*(T1-T)=m2*cw*(T-T2)

m1*(T1-T)=m2*(T-T2)

m1*T1-m1*T=m2*T-m2*T2

m1*T1 +m2*T2=m2*T +m1*T

m1*T1 +m2*T2=T(m2 +m1)

T= (m1*T1 +m2*T2)/(m2 +m1)

T=(0,5*70+0,3*28)/(0,5+0,3)

T=54,25°C