Odpowiedź:
a = [tex]log_{1/4} [10 - 2 ] = log_{1/4} 8 = log_{2^{-2}} 2^3 = - \frac{1}{2} *3*log_22 = -1,5[/tex]
b = [tex]log_3 \frac{3^{-2}*3^{1/3}}{3^{-5}*3^{1/2}} = log_3 3^{2\frac{5}{6} } = 2\frac{5}{6}[/tex]
( a , b )
Odp. - 1 , 0, 1 , 2
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Szczegółowe wyjaśnienie:
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Odpowiedź:
a = [tex]log_{1/4} [10 - 2 ] = log_{1/4} 8 = log_{2^{-2}} 2^3 = - \frac{1}{2} *3*log_22 = -1,5[/tex]
b = [tex]log_3 \frac{3^{-2}*3^{1/3}}{3^{-5}*3^{1/2}} = log_3 3^{2\frac{5}{6} } = 2\frac{5}{6}[/tex]
( a , b )
Odp. - 1 , 0, 1 , 2
====================
Szczegółowe wyjaśnienie: