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SO₃
32/16 * 3 = 32/48 = 2: 3
b) tlenku żelaza (III)
Fe₂O3
112/48= 14/6= 7:3
c) tlenku miedzi (I)
Cu₂O
126/16= 63/8 = 63 :8
d) tlenku krzemu (IV)
SiO₂
28/32 = 14/16= 7 : 8