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Q=cmΔT
Q=ciepło
c=ciepło właściwe
m=masa
ΔT=amplituda temperatury (-10'C-0'C=10'C)
Dane:
m=10kg
c=2100J/kg'C
ΔT=-10'C-0'C=10'C
Szukane:
Q=?
Rozwiązanie:
Q=cmΔT
Q=2100J/kg'C*10kg*10'C=210000J=210kJ