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T₁ = -20 C
T₂ = 0 C
ΔT = 0 C - ( -20 C ) = 20 C
cw = 2100 J/kg * C
ct = 334000 J/kg
Q = ?
Q = Q₁ + Q₂
Q₁ = ogrzanie lodu do temp. topnienia
Q₁ = m *cw * ΔT
Q₁ = 2 kg * 2100 J/kg * C * 20 C
Q₁ = 84000 J = 84 kJ
2. topnienie lodu :
Q₂ = m * ct
Q₂ = 2 kg * 334000 J/kg
Q₂ = 668000 J = 668 kJ
Q = 84 kJ + 668 kJ = 752 kJ