Odpowiedź:
NaBr/bromek sodu/---> delta E = 2,8(Br) - 0,9(Na)=1,9
KCl /chlorek potasu/ --> delta E = 3,0 (Cl ) -0,8(K) =2,2
CaO/tlenek wapnia/ --->delta E = 3,5(O) - 1,0(Ca) =2,5
AlF3 /fluorek glinu/-->deltaE = 4,0(F) - 1,5(Al) = 2,5
Li3N/azotek litu/---> deltaE= 3,0(N) -1,0(Li) =2,0
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Odpowiedź:
NaBr/bromek sodu/---> delta E = 2,8(Br) - 0,9(Na)=1,9
KCl /chlorek potasu/ --> delta E = 3,0 (Cl ) -0,8(K) =2,2
CaO/tlenek wapnia/ --->delta E = 3,5(O) - 1,0(Ca) =2,5
AlF3 /fluorek glinu/-->deltaE = 4,0(F) - 1,5(Al) = 2,5
Li3N/azotek litu/---> deltaE= 3,0(N) -1,0(Li) =2,0