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Odpowiedź:
Wyjaśnienie:
Spalanie biologiczne fruktozy:
C6H12O6 + 6O2 = 6CO2 + 6H2O + 2800kJ
180g
180g fruktozy..............2800kJ
9g...................................x
x = 140kJ
1 cal.................4,19J
x cal................140000J
x = 33412,9 cal ≅ 33kcal