Odpowiedź:
[tex]2|\sqrt{2} -\sqrt{3} |-\sqrt{2} |\sqrt{6} -2|=-2(\sqrt{2} -\sqrt{3} )-\sqrt{2} (\sqrt{6} -2)=\\=-2\sqrt{2} +2\sqrt{3} -2\sqrt{3} +2\sqrt{2} =0 \in N[/tex]
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Odpowiedź:
[tex]2|\sqrt{2} -\sqrt{3} |-\sqrt{2} |\sqrt{6} -2|=-2(\sqrt{2} -\sqrt{3} )-\sqrt{2} (\sqrt{6} -2)=\\=-2\sqrt{2} +2\sqrt{3} -2\sqrt{3} +2\sqrt{2} =0 \in N[/tex]